Is it true that, for $k\geq 4$, \[g_k(n) \gg \frac{n^{1-\frac{1}{k-1}}}{(\log n)^c}\] for some constant $c>0$?
Is it true that, for $k\geq 4$, \[g_k(n) \gg \frac{n^{1-\frac{1}{k-1}}}{(\log n)^c}\] for some constant $c>0$?
The lower bound $R(4,m) \gg m^3/(\log m)^4$ of Mattheus and Verstraete [MaVe23] (see [166]) implies \[g_4(n) \gg \frac{n^{2/3}}{(\log n)^{4/3}}.\] In general it is known (see [BoKe10]) that \[R(k,m)\gg (\log m)^{-O_k(1)}m^{\frac{k+1}{2}}\] which implies \[g_k(n) \gg \frac{n^{1-\frac{2}{k+1}}}{(\log n)^{c_k}}.\]