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PROVED This has been solved in the affirmative.
Let $A\subseteq \{1,\ldots,N\}$ be such that, for all $a,b\in A$, the product $ab$ is not squarefree.

Is the maximum size of such an $A$ achieved by taking $A$ to be the set of even numbers and odd non-squarefree numbers?
A problem of Erdős and Sárközy.

Weisenberg has provided the following positive proof. It is clear that such a maximal $A$ must contain all non-squarefree numbers. It therefore suffices to find the largest size of a subset of all squarefree numbers in $\{1,\ldots,N\}$ such that any two have at least one prime factor in common. By the result of Chvátal [Ch74] discussed in [701] this is maximised by the set of all even squarefree numbers.

An alternative proof was independently found by Alexeev, Mixon, and Sawin [AMS25].

See also [848].

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Additional thanks to: Desmond Weisenberg

When referring to this problem, please use the original sources of Erdős. If you wish to acknowledge this website, the recommended citation format is:

T. F. Bloom, Erdős Problem #844, https://www.erdosproblems.com/844, accessed 2025-11-16